May's Problem was:
Karen is making a bracelet for her grandmother. How much does each black bead cost? How much does each white bead cost? How much will the whole bracelet cost if Karen used 9 black beads and 9 white beads?
May's Answer was:
Black beads cost $0.20 each.
White beads cost $0.35 each.
The whole bracelet cost $4.95 to make.
There are many ways you could have solved this problem. How did you solve it? Post your strategy on the home page.
April's Problem was:
Three views of the same cube which has a letter on each of its faces are shown. Also given is a net for the cube but with only one of the letters marked on it. The challenge is to mark in all the other letters, getting their positions and their orientations correct, without resorting to the use of a model cube (though if that helps, you can use one). How good is your three-dimensional perception?
(Bolt, 1993)
March's Problem was:
Karen is making a bracelet for her grandmother. How much does each black bead cost? How much does each white bead cost? How much will the whole bracelet cost if Karen used 9 black beads and 9 white beads?
Clue - 2 white beads and 1 black bead cost $.90
Clue - 2 white beads and 2 black beads cost $1.10
(shared by a teacher in the CMAG project)
May's Answer was:
Black beads cost $0.20 each.
White beads cost $0.35 each.
The whole bracelet cost $4.95 to make.
There are many ways you could have solved this problem. How did you solve it? Post your strategy on the home page.
April's Problem was:
Three views of the same cube which has a letter on each of its faces are shown. Also given is a net for the cube but with only one of the letters marked on it. The challenge is to mark in all the other letters, getting their positions and their orientations correct, without resorting to the use of a model cube (though if that helps, you can use one). How good is your three-dimensional perception?
March's Problem was:
Take a sheet of any newspaper. Tear it in half and put the two pieces together. Now tear the two pieces in half and put them on top of each other to form a pile of four pieces. Tear the four pieces in half and put them on top of each other to form a pile of eight pieces. Imagine yourself repeating this process 10 times. How many pieces would you have in your pile? How many would you have if you repeated the process 40 times?
For a challenge, assume a single piece of paper to be one hudredth of a centimeter thick. What would the height be for your piles?
March's answer:
2*2*2*2*2*2*2*2*2*2 or 2 to the 10th power = 1,024 pieces of paper if ripped 10 times which would be .01*1024 = 10.24 cm thick
2 to the 40th power = 1,099,511,627,776 pieces of paper if ripped 40 times, which would be 10,995,116,277.76 cm thick
There were more ways than this to solve the problem. How did you solve it?
(Adapted from Bolt, 1993)
February's Problem was: A mule and a donkey were walking along laden with sacks of corn. The mule said to the donkey, "If you gave me one of your sacks of corn, I would be carrying twice as much as you. But if I gave you one, we both would be carrying equal burdens." How many sacks of corn were they each carrying?
(Bolt, 1993)
February's Answer:
The mule had 7 sacks and the donkey had 5 sacks there many was to solve this problem how did you solve it?
